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how do you factor this polynomial
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\[(1/8) a ^{3} - b ^{3}\]
yes it is, i know how to do it if it was 8 but 1/8 ??
its just like 8
\[x^3-y^3=(x-y)(x^2+xy+y^2)\]this time ur x is a/2 am i right?
oh ok thanks
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8=2^3
1/8=2^-3
which is the same as 1/2^3
yeah
so should i just write it in the form of a fraction?
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well yes \[\frac{a^3}{8}=\frac{a^3}{2^3}=(\frac{a}{2})^3\]
yeah thats what I thought :) thanks
:)
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