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Mathematics 7 Online
OpenStudy (anonymous):

how do you factor this polynomial

OpenStudy (anonymous):

\[(1/8) a ^{3} - b ^{3}\]

OpenStudy (anonymous):

yes it is, i know how to do it if it was 8 but 1/8 ??

OpenStudy (anonymous):

its just like 8

OpenStudy (anonymous):

\[x^3-y^3=(x-y)(x^2+xy+y^2)\]this time ur x is a/2 am i right?

OpenStudy (anonymous):

oh ok thanks

OpenStudy (unklerhaukus):

8=2^3

OpenStudy (unklerhaukus):

1/8=2^-3

OpenStudy (anonymous):

which is the same as 1/2^3

OpenStudy (anonymous):

yeah

OpenStudy (anonymous):

so should i just write it in the form of a fraction?

OpenStudy (anonymous):

well yes \[\frac{a^3}{8}=\frac{a^3}{2^3}=(\frac{a}{2})^3\]

OpenStudy (anonymous):

yeah thats what I thought :) thanks

OpenStudy (anonymous):

:)

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