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If an object is dropped from a height of 144 feet, the function h(t)=16t^2+144 gives the height of the object after t seconds. When will the object hit the ground? A. 9 s B. 6 s C. 1.5 s D. 3 s
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(B)
presumably it is \(h(t)=-16t^2+144\) set \(-16t^2+144=0\) solve in 3 steps
\[16t^2=144\] divide by 16, take the square root
9
hold on
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\[144\div 16=9\] so you have \(t^2=9\) but you want \(t\) not \(t^2\) what number squared is 9 ?
3
you win
(D)
thanks
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yw
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