Mathematics
15 Online
OpenStudy (anonymous):
I need help with the attached problem.
Join the QuestionCove community and study together with friends!
Sign Up
OpenStudy (anonymous):
OpenStudy (anonymous):
In y=mx+c can u tell me what is the slope?
OpenStudy (anonymous):
m = slope
OpenStudy (anonymous):
So, V(t)=-203t+9655........ what do u think is the slope
OpenStudy (anonymous):
-203 = m = slope
Join the QuestionCove community and study together with friends!
Sign Up
OpenStudy (anonymous):
Now, since slope is negative it means it is decreasing at the rate of 203 per year
OpenStudy (anonymous):
So the value of the Gremlin is decreasing at the rate of 203 per year?
OpenStudy (anonymous):
yep
OpenStudy (anonymous):
Now, what do u think V intercept is?
OpenStudy (anonymous):
V represents the value in year t. So, in 1974, V(1974) = -203(1974)+9655
Join the QuestionCove community and study together with friends!
Sign Up
OpenStudy (anonymous):
At 1974, t=0
OpenStudy (anonymous):
got it?
OpenStudy (anonymous):
Yes. So what would V be then?
OpenStudy (anonymous):
9655
OpenStudy (anonymous):
Okay. And what would be the meaning of the V-intercept in this application?
Join the QuestionCove community and study together with friends!
Sign Up
OpenStudy (anonymous):
Value of Albert Gebra's at 1974
OpenStudy (anonymous):
Okay, thanks. Now I have to find the t-intercept for the application and explain what this means in terms of the application.
OpenStudy (anonymous):
V(t)=0
OpenStudy (anonymous):
Now, -203t+9655=0
OpenStudy (anonymous):
So after you solve for t, I get 47.562
Join the QuestionCove community and study together with friends!
Sign Up
OpenStudy (anonymous):
It represents after 47.562 years the Albert ... value will be zero
OpenStudy (anonymous):
Okay. And if I have to sketch a graph of the function, labeling the axis, scale and equation, how would I do that?
OpenStudy (anonymous):
|dw:1346511852592:dw|