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Mathematics 15 Online
OpenStudy (anonymous):

I need help with the attached problem.

OpenStudy (anonymous):

OpenStudy (anonymous):

In y=mx+c can u tell me what is the slope?

OpenStudy (anonymous):

m = slope

OpenStudy (anonymous):

So, V(t)=-203t+9655........ what do u think is the slope

OpenStudy (anonymous):

-203 = m = slope

OpenStudy (anonymous):

Now, since slope is negative it means it is decreasing at the rate of 203 per year

OpenStudy (anonymous):

So the value of the Gremlin is decreasing at the rate of 203 per year?

OpenStudy (anonymous):

yep

OpenStudy (anonymous):

Now, what do u think V intercept is?

OpenStudy (anonymous):

V represents the value in year t. So, in 1974, V(1974) = -203(1974)+9655

OpenStudy (anonymous):

At 1974, t=0

OpenStudy (anonymous):

got it?

OpenStudy (anonymous):

Yes. So what would V be then?

OpenStudy (anonymous):

9655

OpenStudy (anonymous):

Okay. And what would be the meaning of the V-intercept in this application?

OpenStudy (anonymous):

Value of Albert Gebra's at 1974

OpenStudy (anonymous):

Okay, thanks. Now I have to find the t-intercept for the application and explain what this means in terms of the application.

OpenStudy (anonymous):

V(t)=0

OpenStudy (anonymous):

Now, -203t+9655=0

OpenStudy (anonymous):

So after you solve for t, I get 47.562

OpenStudy (anonymous):

It represents after 47.562 years the Albert ... value will be zero

OpenStudy (anonymous):

Okay. And if I have to sketch a graph of the function, labeling the axis, scale and equation, how would I do that?

OpenStudy (anonymous):

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