Ask your own question, for FREE!
Mathematics 21 Online
OpenStudy (anonymous):

asap!!! help = fanning

OpenStudy (anonymous):

What is the exact value of the expression\[11 \sqrt{8} + 6\sqrt{12}- 5 \sqrt{2}\]

OpenStudy (lgbasallote):

can i ask if you have fanned me yet?

OpenStudy (anonymous):

Show your work

OpenStudy (anonymous):

oh sorry yeah i did

OpenStudy (anonymous):

Hint: make them all inside the radical and then solve from there.

OpenStudy (anonymous):

As in, make the outside numbers go back into the radical.

OpenStudy (anonymous):

ookk step by step plz

OpenStudy (anonymous):

I'll give you a link. http://regentsprep.org/Regents/math/ALGEBRA/AO1/Laddsubt.htm

OpenStudy (anonymous):

ok

OpenStudy (anonymous):

still dont get it

OpenStudy (lgbasallote):

hint: \[11 \sqrt 8 \implies 11 \times \sqrt 8 \implies 11\times \sqrt{4 \times 2} \implies 11 \times 2\sqrt 2 \implies 22\sqrt 2\] \[6\sqrt {12} \implies 6 \times \sqrt{12} \implies 6 \times \sqrt{4 \times 3} \implies 6 \times 2\sqrt 3 \implies 12\sqrt 3\] does that help?

OpenStudy (anonymous):

yeah

OpenStudy (anonymous):

@lgbasallote explained well. Thank you.

OpenStudy (anonymous):

or in this case, hinted well.

OpenStudy (anonymous):

@zahabaha I'm sorry but it violates the Terms of Conduct of OS to simply give out answers to users. In fact, we get warned because of giving answers out.

OpenStudy (anonymous):

If you have the time, we can guide you step by step but you need to show us your working and we can guide you through it.

OpenStudy (anonymous):

whos iqba

OpenStudy (anonymous):

The user with the green username.

OpenStudy (anonymous):

okkk

Can't find your answer? Make a FREE account and ask your own questions, OR help others and earn volunteer hours!

Join our real-time social learning platform and learn together with your friends!
Can't find your answer? Make a FREE account and ask your own questions, OR help others and earn volunteer hours!

Join our real-time social learning platform and learn together with your friends!