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F(x)=x^2 -10x+27, x>5; find the inverse
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First take it to the completed square form
Like :x-27=y(y-10)?
Or no?
F(x)=x^2 -10x+27 =x^2-2*x*5+5^2-5^2+27 =(x-5)^2+2
Solve[ y == x^2 - 10 x + 27,x] \[ x=\sqrt{y-2}+5 \\ y=\sqrt{x-2}+5 \]
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