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Line that is parallel to the like 2y-4x=10 and goes through the point (-3,-7)
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Lines that are parallel have the same slope so first you must put the equation into y=mx+b (slope intercept form) \[2y=4x+10\] \[y=2x+5\] now that you know the slope (m) , you can use the point slope form \[y-y_1=m(x-x_1)\] where \[(x_1,y_1)\] is a point on the line you are trying to find the equation to
yes i need to find the equation
i got y=2x+1 is this right?
\[y-(-7)=2(x-(-3)\] \[y+7=2(x+3)\] \[y+7=2x+6\] \[y+7-7=2x+6-7\] \[y=2x-1\]
thanks
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