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What is the vertex of the parabola x = 5(y – 4)2 – 1 ?
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solve for y. and then put it into a grapghing calculator. im sure that will help
y=4 implies that x =-1
(-1,4) is the vertex
There is a vertex formula. Use the quadratic equation \[-b \pm \sqrt{b^2-4(a) (c)\ }{ ? }\]
all over 2a. FOrget the ? mark.
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To find the vertex, use \[\frac{ -b }{ 2a } and plug \in\]
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