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Mathematics 7 Online
OpenStudy (anonymous):

For "x" such that 0 < x < π/2, what is the value of √(1-sin^2x)/sin x * √(1-cos^2 x)/ cos x? sin x cos x tan x 1 2

OpenStudy (cwrw238):

√(1-sin^2x) = cos x √(1-cos^2x) = sin x

OpenStudy (anonymous):

so which one is it?

OpenStudy (cwrw238):

replace the two square root terms using the above identities and it will be easy

OpenStudy (anonymous):

i'm new to trigonometry

OpenStudy (cwrw238):

you don't need to know a lot of trigonometry - what do you get when you do the replacements?

OpenStudy (cwrw238):

eg instead of √(1-sin^2x) you put cos x

OpenStudy (anonymous):

so it's cos x/ sin x ?

OpenStudy (cwrw238):

thats a part of it - whats the second part of the multiplication equal to?

OpenStudy (anonymous):

um... idk

OpenStudy (cwrw238):

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