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Mathematics 14 Online
OpenStudy (anonymous):

A fence is to be installed around a rectangular field. The field's perimeter is 200 feet. Find the dimensions of the field if the length of the field is 2 feet more than the width. (The figure shows W+2 as the width and W as the height.

OpenStudy (anonymous):

Let x ft be the width of the rectangular field then , length of the field = x+2 ft Now, perimeter = 200

OpenStudy (anonymous):

Does it help?

OpenStudy (anonymous):

Not exactly

OpenStudy (anonymous):

perimeter = 2(l+b) 200=2(x+2+x)

OpenStudy (anonymous):

Can u solve for x

OpenStudy (anonymous):

I got 49 for feet. How do I solve for width?

OpenStudy (anonymous):

x=49ft

OpenStudy (anonymous):

Never mind, I just insert that into the forumla. Okay, I got it now. Thanks for your time and help.

OpenStudy (anonymous):

length=x+2=49+2=51ft width=x=49ft

OpenStudy (anonymous):

got it?

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