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A fence is to be installed around a rectangular field. The field's perimeter is 200 feet. Find the dimensions of the field if the length of the field is 2 feet more than the width. (The figure shows W+2 as the width and W as the height.
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Let x ft be the width of the rectangular field then , length of the field = x+2 ft Now, perimeter = 200
Does it help?
Not exactly
perimeter = 2(l+b) 200=2(x+2+x)
Can u solve for x
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I got 49 for feet. How do I solve for width?
x=49ft
Never mind, I just insert that into the forumla. Okay, I got it now. Thanks for your time and help.
length=x+2=49+2=51ft width=x=49ft
got it?
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