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For the function f(x)= |3x-17|, what is one possible value of "a" for which f(a)
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@Callisto
Where is the Expression INSIDE the abs-brackets small - this is the way to solve... follow it
The number itself will NOT be small....
those are aboslute value signs
Yes, of course. Once again: think where [for which x] the Expression inside will be small.
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how can i solve this?
By trial and error, perhaps. Example: f(4) = |3(4) - 17| = |12-17| = |-5| = 5 > 4, so 4 is NOT the answer.
hmmmmmmm.........
Or you can solve it in fact. f(a) < a |3a - 17| < a -a < 3a-17 < a Solve a.
You'll get something like __ < a < __ And you can get all values of a satisfying the inequality.
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