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OpenStudy (anonymous):
If x=3a+7 and y=9a^2, what is y in terms of x? (x-7)^2 3(x-7)^2 (x-7)^2/3 (x+7)^2/3 (x+7)^2
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OpenStudy (anonymous):
From x=3a+7 x-7=3a a=(x-7)/3
OpenStudy (anonymous):
Subsitute the value of a in y=9a^2
OpenStudy (anonymous):
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