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If a=2b, 3b=4c, and 5c=6d, what is the ratio of a to d?
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given a=2b 3b=4c 5c = 6d substitute the value of c from eqn 2 in eqn 3 5 (3b/4) = 6d 15b = 24 d d = 15b/24 now divide the first eqn by the above one to find the ratio....
the 1st equation is 5c = 6d?
no a = 2b is the first eqn
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