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solve for F c=5/9(F-32)
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\[c= \frac{5}{9f-288}\]
\[(9f-288)=\frac{5}{c}\]See it now?
nope i dont see how you got the first step
Multiplies everything in the brackets by 9 9(f-32)=9f-288
=9f-9*32
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this is the formula for converting from Fahrenheit to Celsius it is \[C=\frac{5}{9}(F-32)\]
I think you're over-complicating this. 1) Multiply both sides by 9/5 A 2) Add 32 to each side 3) Simplify
to go the other way, solve for \(F\)
what @Shane_B said
(disregard the A above...typo :)
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Following what I said: \[C=\frac{5}{9}(F-32)\]\[\frac{9}{5}C=F-32\]\[\frac{9}{5}C+32=F\]
aah,,,ok,, thank you very much
yw
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