find area of trainagle 1 1/4 is base and height is 4/9
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OpenStudy (cwrw238):
area = half of the base * the height
OpenStudy (anonymous):
i got 1 1/9 is that correct
OpenStudy (anonymous):
No, that's not right. I'm working it out right now
OpenStudy (anonymous):
It's equivalent to .277777778
OpenStudy (anonymous):
how did you get that
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OpenStudy (phi):
Can you change the base to an improper fraction?
OpenStudy (anonymous):
half of 1 and 1/4 is .625. and then multiply that by 4/9 and you get .27777778
OpenStudy (anonymous):
phi yes you can
OpenStudy (phi):
The formula for the area of a triangle is
\[ A= \frac{1}{2} b\cdot h\]
where b is the base and h is the height (or altitude)
the easiest way is to change the base \(= 1 \frac{1}{4}\) to an improper fraction then multiply the fractions b*h
then multiply by 1/2
OpenStudy (phi):
I know I can. Can you? if so what is it?
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OpenStudy (anonymous):
5/4
OpenStudy (phi):
now multiply the fractions
\[ \frac{1}{2}\cdot\frac{5}{4}\cdot \frac{4}{9} \]
multiply tops, and multiply bottoms
(but you can simplify by first cancelling the 4's)
OpenStudy (anonymous):
5/4 times 4/9= 20/36 then do i multiply by half
OpenStudy (phi):
yes
OpenStudy (anonymous):
is its 5/18
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OpenStudy (phi):
but notice it is easier to first cancel the 4's
You can do that because order does not matter.
\[ \frac{1}{2}\cdot\frac{\cancel{4}}{\cancel{4}}\cdot \frac{5}{9} = \frac{5}{18}\]