Question

please help, ray BD is the bisector of angle ABC, find angle ABC angle CBD and angle DBA when angle ABD= 2x^2 and angle ABC=100

Answer 1

Well, angle ABC is given and is the whole. Because of the bisection, angle ABD is half of the whole. angle CBD is congruent because it is also half.

Answer 2

You don't even need to solve for x here, just find half of 100.

Answer 3

Ok.. so ABC = ABD + CBD

then CBD = ABC - ABD

CBD = 2x^2

since BD is a bisector

so ABC = 2x^2 + 2x^2 or

100 = 4x^2

solve for x