Question

Write the equation of the line that is parallel to the line 4x − 3y = −12 and passes through the point (−3, 4).

y = x + 8 x= 4over3

y = x + 3 x=4over3

y = −x + 8 -x= -3over4

y = −x + 3 -x= -3over4

Answer 1

4x − 3y = −12

-3y = -4x - 12

y = 4/3x + 4

So the slope is 4/3

Answer 2

Any parallel line will also have a slope of 4/3

Answer 3

y = mx+b

y = (4/3)x + b

4 = (4/3)(-3) + b

4 = -12/3 + b

4 = -4 + b

4+4 = b

8 = b

b = 8

So the equation of the parallel line is \(\Large y = \frac{4}{3} x + 8\)