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0.66 = log(x)
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Solve for \(\log_{10}(x)\):\[ 10^{0.66}=10^{\log_{10}(x)}=x \]Replace 10 with whatever base you're working in.
could you explain that a little further for me. i really do not understand logs.
All right, we define: \[ \log_a(b)=c \implies \\ a^c=b \implies \text{By substitution of $c$}\implies\\ a^{\log_a(b)}=b \]
thanks
Sure thing.
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