Question

13x^2+7=0

Answer 1

13x^2+7=0
13x^2=-7
x^2=-7/13
x=rad-7/13
can't have a negative number inside a radical/square root so it's no solution

Answer 2

\[\sqrt{-1}=i\]

Answer 3

or you can answer it as imaginary

Answer 4

I think the answer would be \[x=\sqrt{7/13}i\]
Then you would want to rationalize the denominator by multiplying \[\sqrt{7/13} by \sqrt{13/13}\]