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Please simplify the following with steps. Thank you... (x^3)-1
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\[\Large x^3 - 1 \implies x^3 - 1^3\] this is difference of two cubes \[\Large a^3 - b^3 \implies (a-b)(a^2 + ab + b^2)\] does that help?
yes thank you
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Does the same principle work for (x^3)+8?
\[x^3 + 8\] that's sum of cubes \[\implies x^3 + 2^3\] the sum of cubes formula is \[a^3 + ^3 \implies (a+b)(a^2 - ab + b^2)\]
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Got it, thanks
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