Question

I need to create a new array of size N, as specified by the user. I'm using c++.

Answer 1

first take the size from the user then assign this size to array , like
cin >> size;
int arr[size];
if it is helpful for you let me know.

Answer 2

It gives me the following errors:
Expected constant expression.
Cannot allocate an array of constant size zero.
'numbers' unknown size.

Where "numbers" is the name of the array. I also used #define input cin >> at the beginning so i can just use "input size;" Dont think that would make a difference.

Answer 3

yes in c++ you can't assign 0 size to an array
size must be greater than 0

Answer 4

yes, thats just from the previous error. The problem is the first error.

Answer 5

Should i post my code?

Answer 6

yes

Answer 7

#include <iostream>
using namespace std;

#define print cout <<
#define input cin >>

int main() {
int N;
print "How many integers?\n";
input N;
int numbers[N];

for(int i; i < N; i++) {
int n;
print "Number " << numbers << ": ";
input n;
numbers[i] = n;
}
}

Forgot what i was doing in the for loop, oddly enough, but the problem is before that. The red underline is under the 'N' in the array declarator. It says, "expression must have a constant value".

Answer 8

you want to print your arrays values ???? numbers ????

Answer 9

i was in the middle of working on that loop when i decided to ask the community.

Answer 10

I dont think the for loop has anything to do with the declaration of the array.

Answer 11

yes

Answer 12

http://cboard.cprogramming.com/cplusplus-programming/82221-user-input-array-size.html

Answer 13

it will help you , use number=new number[size]; then tell me

Answer 14

I realize what it was:

for(int i; i < N; i++) {
int n;
print "Number " << numbers[i] << ":";
input n;
numbers[i] = n;
}

Answer 15

now you are printing it correctly , tell me size issue has resolved or not?

Answer 16

syntax error. need to put tpe specifier?

Answer 17

found something in that link you sent. let me check.

Answer 18

ok

Answer 19

Thanks you very much! the answer was in the third response in the link.

Answer 20

there is someone in need of a wizard with c++. scroll down in the computer science category for Wiisper.

Answer 21

actually arrays takes the constant size , it is compiler dependent , cz when i used to declare arrays like this , it worked well , i never used new for this kind of initializing

Answer 22

Different compilers. im using microsoft visual studio 2010. i really need to learn pointers. Anyway, someone else needs more help.