Question

perimeter of rectangle is 40ft. length is 8ft longer then width. Find dimensions let x be length and y width
2x+2y=

Answer 1

2x+2y=40
l=w+8
2(w+8)+2w=40
2w+16+2w=40
4w=24
w=6

Answer 2

switch all the w's to y

Answer 3

Here:
\[
2l+2w=40\\
l=8+w
\]Substituting:
\[
2(8+w)+2w=40\\
16+4w=40\\
4w=24\\
w=6\\
l=8+6=14
\]

Answer 4

thanks