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Mathematics 4 Online
OpenStudy (anonymous):

In this triangle, what does cscA*cscB equal?

OpenStudy (anonymous):

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OpenStudy (anonymous):

csc = hypotenuse/opposite = 4/x

OpenStudy (anonymous):

is that the whole picture?

OpenStudy (anonymous):

yep, that's the whole picture.

OpenStudy (anonymous):

there's no B...

OpenStudy (anonymous):

i made a typo. cscA*cotB

OpenStudy (anonymous):

that's where I was getting confused too.

OpenStudy (anonymous):

oh i see, then that's easier cscA=4/x cotB=x/4 cscA*cotB=4/x * x/4=1

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