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How would you find the solution to the equation x^4-64=0?
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Diffrence of squares. Factor away!
(a^2-b^2) = (a-b)(a+b) here a = x^2 and b = 8 so (x^2-8)*(x^2+8) make sense?
add 64 to the other side. 4 root of both sides. so 4th root of 64 = x
nono cant do that @crazykidguy
we will have 4 answers
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2 with imaginary parts
+-sqrt(-8) and +-sqrt(8)
Factor |dw:1346494552802:dw|
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