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An integer between 100 and 999, inclusive, is chosen at random. What is the probability that all three digits of the number are different odd numbers?
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9*9*8?
oh wait odd numbers 5*4*3?
how i think about these problems the first number can either be 1,3,5,7,9 thats 5 different choices since you picked a number for the first choice, that leaves 4 left and for the 3rd number, 3 numbers are left there are a total 999-100 numbers to choose from
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