Question

A blue ball is thrown upward with an initial speed of 20.0 m/s, from a height of 0.7 meters above the ground. 2.4 seconds after the blue ball is thrown, a red ball is thrown down with an initial speed of 9.8 m/s from a height of 22.6 meters above the ground. The force of gravity due to the earth results in the balls each having a constant downward acceleration of 9.81 m/s2.

Answer 1

1.) What is the speed of the blue ball when it reaches its maximum height?
3.) How long does it take the blue ball to reach its maximum height?
4.) What is the maximum height of the blue ball reaches?
5.) What is the height of the red ball 3.12 seconds after the blue ball is thrown?
6.) How long after the blue ball is thrown are the two balls in the air at the same height?

I'm having trouble understanding this problem and how to start with what equations to use on a step by step process.. Please help.....