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Mathematics 11 Online
OpenStudy (anonymous):

For the next 8 questions use the kite inscribed in circle p. 1. If the measure of arc BC is 63 degrees, calculate m

OpenStudy (anonymous):

OpenStudy (anonymous):

@hartnn @ganeshie8

hartnn (hartnn):

1. measure of arc is same as that it inscribes at centre.so whats m<BPC=?

OpenStudy (anonymous):

63?

OpenStudy (anonymous):

degrees*

hartnn (hartnn):

yup.

hartnn (hartnn):

2. since AB=BC,measure of arc AB also = 63 so whats measure of arc AC?

OpenStudy (anonymous):

126 degrees

hartnn (hartnn):

yup. 3. done,ok? true or false? 4. can u prove AED and CED triangles congruent?

OpenStudy (anonymous):

3's done?

OpenStudy (anonymous):

And yes CED and AED are congruent.

ganeshie8 (ganeshie8):

just now we found measure of arc AB=63. so... ?

OpenStudy (anonymous):

False?

ganeshie8 (ganeshie8):

yup. and it is possible for having a 90 degrees in kite. so tick False !

hartnn (hartnn):

since those triangles are congruent,can u say AD=CD?

OpenStudy (anonymous):

yup

hartnn (hartnn):

so 4. is yes. 5. i don't think there is anyway to show that BCD=90, 6. already proved that in 2.

OpenStudy (anonymous):

7. true as well?

hartnn (hartnn):

yup,because both angles are subtended by same arc BC

OpenStudy (anonymous):

5. not possible, or false?

ganeshie8 (ganeshie8):

im thinking of 5th Q.... i dont see anyway to prove it using kite properties. but it is angle in semi-circle. so its a right angle... .

hartnn (hartnn):

oh yes! agle BCD is 90 degree as @ganeshie8 said.

OpenStudy (anonymous):

okay so true for 5.

hartnn (hartnn):

now angle subtended by an arc on the circle is half the angle subtended at center. so angle BDC = 1/2 *BPC =1/2 arc BC =??

hartnn (hartnn):

^^ was 8. yup true for 5.

OpenStudy (anonymous):

31.5?

hartnn (hartnn):

and 7. true because both angles are subtended by same arc BC

OpenStudy (anonymous):

okay.

hartnn (hartnn):

yes,31.5 degrees for 8.

OpenStudy (anonymous):

thank you SO MUCH

hartnn (hartnn):

got all?

hartnn (hartnn):

welcome :)

hartnn (hartnn):

ok,m ready for your next question ;)

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