The perimeter of a rectangle is 30 ft. The length is 5 ft longer than the width. Find the dimensions. Write a system of linear equations and solve the resulting systems. Let x be the length and y be the width.

Write first equation.
2x + 2y= _______

Write Second equation.
x=y+_____
What is the length?______ft
What is the width?_______ft

Question

The perimeter of a rectangle is 30 ft. The length is 5 ft longer than the width. Find the dimensions. Write a system of linear equations and solve the resulting systems. Let x be the length and y be the width. 

Write first equation. 
2x + 2y= _______

Write Second equation.
x=y+_____
What is the length?______ft
What is the width?_______ft

zzr0ck3r · Answer

2x+2y = 30

x = y+5

where x is length

zzr0ck3r · Answer

2x+2y = 30
x-y = 5  now multiply the second one by -2

system is now
2x+2y = 30
-2x+2y = -10
add them together
4y = 20
y = 5
x = y+5 = 5+5 = 10

zzr0ck3r · Answer

make sense @WrittenOnMyHeart ?

anonymous · Answer

Yeah, it does. The length is 10 and the width is 5.

zzr0ck3r · Answer

yes but do you see how I got there?

anonymous · Answer

Yes. I see it's the very first step that always gets me. Guessing a working number or whatever you call it.