Question

use only Boolean algebra to simplify the Boolean expression F. (first determine f1 and f2, then simplify f1 +f2) showing all steps
f1 = ywx' + yw'x'
f2 = (y' + xw)'
F(w, x,y) = F1+F2.
please assist

Answer 1

F1 = ywx' + yw'x'
= yx'(w+w')
= yx'
F2 = (y'+xw)'
= (y')'.(xw)'
= y(x'+w')
= yx' + yw'
Therefore : F1 + F2 = yx' + yx' + yw
= yx' + yw

Answer 2

Many tnx

Answer 3

Anytime.. . :)