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Physics 20 Online
OpenStudy (anonymous):

A boy sledding down a hill accelerates at 1.30 m/s2. If he started from rest, in what distance would he reach a speed of 8.80 m/s? ______m

OpenStudy (anonymous):

gonna help?

OpenStudy (anonymous):

use the third equation of motion

OpenStudy (anonymous):

what is that?

OpenStudy (anonymous):

\[v^{2} = u^{2} + 2as\]

OpenStudy (anonymous):

can u plug in the numbers for me with a drawing?

OpenStudy (anonymous):

started from rest means u = 0 v is 8.8 a = 1.3 s is to be found

OpenStudy (anonymous):

can you use draw and draw the equation with the number in it for me?

OpenStudy (anonymous):

|dw:1346691332026:dw|

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