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OpenStudy (chihiroasleaf):
what is the question?
OpenStudy (anonymous):
im trying to find the trinomial factorization
OpenStudy (anonymous):
the correct answer is 2x(3x-2)(x-4) i just don't know how to get it
OpenStudy (chihiroasleaf):
First, find the common factor of all term,
\[6x ^{3}-28x ^{2}+16x\]
can you tell what is the common factor of 6x^3, 28x^2, and 16x ?
OpenStudy (anonymous):
2x right?
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OpenStudy (chihiroasleaf):
yes, now you can factor the expression
what is the result if you factor out 2x ?
OpenStudy (anonymous):
2x(3x^2-14x+8x)
OpenStudy (chihiroasleaf):
yes...,
now you should factor the expression in the bracket,
can you factroze it?
OpenStudy (anonymous):
how do i do that?
OpenStudy (anonymous):
is it 3x^2-6x^2
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OpenStudy (chihiroasleaf):
wait.., I think you did a little mistake before, the last term is 16x, so if you factor 2x, it should be 8 in the bracket
so, you should get 2x(3x^2-14x+8)
OpenStudy (anonymous):
ok and then what do i do from there
OpenStudy (chihiroasleaf):
to factor \[3x ^{2}-14x+8\]
you will separate -14x become ax+bx such that
a+b = -14 and ab=3 x 8 = 24
can you find a and b?