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f(x) = sin2x g(x)= cos(30'-x) Determine algebraically the value of x for which f(x) = g(x)
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pls help
sin2x=cos(30-x) cos(30-x)=cos30cosx+sin30sinx
so how did you solve
?
stop!
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i was wrong cosx=sin(90-x cos(30-x)=sin(90-(30-x))
sin(60+x)
sin2x=sin(60+x)
do you see it?
do you see how i got there?
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2X=60+X
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