Solve the inequality

1/9 |5x-3|-3 ≥ 2

??

Question

Solve the inequality 

1/9 |5x-3|-3 ≥ 2 

??

anonymous · Answer

I got $$x \ge 53/5 $$ or $$x \le -47/5$$

jim_thompson5910 · Answer

1/9 |5x-3|-3 ≥ 2

1/9 |5x-3| ≥ 2+3

1/9 |5x-3| ≥ 5

|5x-3| ≥ 5*9

|5x-3| ≥ 45

5x-3 ≥ 45  or  5x-3 ≤ -45

I'll let you finish

anonymous · Answer

@jim_thompson5910 Ok! Thank you! :) I got x ≥ 48/5 or 5 ≤ -42/5

Do you have an idea of how I could graph that??

jim_thompson5910 · Answer

did you mean x ≥ 48/5 or x ≤ -42/5 ?

jim_thompson5910 · Answer

To graph this, convert each fraction to a decimal 

48/5 = 9.6

-42/5 = -8.4

So 

x ≥ 48/5 or x ≤ -42/5 

is the same as 

x ≥ 9.6 or x ≤ -8.4

Now draw out a number line. Plot closed circles at x = 9.6 and x = -8.4

Then shade to the left of -8.4 and to the right of 9.6 and it will look something like this

|dw:1346713609885:dw|