Mathematics
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OpenStudy (anonymous):
how do i solve the square root of 7x-1=5
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OpenStudy (anonymous):
r u solving for x
/
OpenStudy (anonymous):
*?
OpenStudy (anonymous):
yes
OpenStudy (anonymous):
i believe so...
OpenStudy (anonymous):
.925
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OpenStudy (anonymous):
how did you solve it?
OpenStudy (anonymous):
lol is it right?
OpenStudy (anonymous):
idk... i was the one asking u...
OpenStudy (anonymous):
is your question, solve for x :
\[\sqrt{(7x-1)} = 5\]?
OpenStudy (anonymous):
it just says "Solve." but your equation is right
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OpenStudy (anonymous):
yeah question is ambiguous. did chi get it right
?
OpenStudy (anonymous):
ok, then the first thing you do is square both sides
OpenStudy (anonymous):
theyre workin on it...
OpenStudy (anonymous):
o to get rid of the square root...
OpenStudy (anonymous):
3.57 should be the ans. squr root both sides to get rid of the rad that solve for x
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OpenStudy (anonymous):
Were you able to finish the problem? the answer isnt 3.57 -_-
OpenStudy (anonymous):
or 25/7 (same thing)
OpenStudy (anonymous):
workin on it...
OpenStudy (anonymous):
i got 26/7
OpenStudy (anonymous):
yup that is correct :)
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OpenStudy (anonymous):
yeah me!!!! Thanks a million!!!!
OpenStudy (anonymous):
sorry chi u were right 26/7 aka 3.17
OpenStudy (anonymous):
actually it would be aka 3.71... right
OpenStudy (anonymous):
np, and yeah 3.71, pierce probably just mistyped
OpenStudy (anonymous):
yeah. sorry
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OpenStudy (anonymous):
yeah it figures! :) thanks everyone!