Question

solve

x^3-5x >= 4x^2

Answer 1

(greater than or equal to)

Answer 2

\[x^3 - 5x \ge 4x^2\]
subtract 4x^2 from both sides
\[\implies x^3 - 4x^2 - 5x \ge 0\]
factor out x
\[\implies x(x^2 - 4x - 5) \ge 0\]
factor out the trinomial
\[\implies x(x-5)(x+1) \ge 0\]
does that help?

Answer 3

I got that far, I just need to know the solutions written as integrals.

Answer 4

Actually, I got it from here. Thanks!