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solve for x!!! sin2x=cosx
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sin2x=cosx 2sinxcosx=cosx 2sinxcosx - cosx = 0 cosx(2sinx - 1) = 0 take cosx=0 and 2sinx - 1 = 0 find x
it does help?
and i think this problem need interval for x...
yes the interval is [0,2pi]
and how did you get 2sinxcosx from sin2x? is that a formula?
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yea, that is a formula ... Ok, for cosx=0, so what wiil u get for x?
pi/2 and 3pi/2 i got the rest of the answers thank you:)
ok right... and for 2sinx - 1 = 0 or sin x = 1/2 solve for x, i sure u can get it to....
pi/6 and 5pi/6
good job...
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