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Mathematics 4 Online
OpenStudy (anonymous):

solve for x!!! sin2x=cosx

OpenStudy (raden):

sin2x=cosx 2sinxcosx=cosx 2sinxcosx - cosx = 0 cosx(2sinx - 1) = 0 take cosx=0 and 2sinx - 1 = 0 find x

OpenStudy (raden):

it does help?

OpenStudy (raden):

and i think this problem need interval for x...

OpenStudy (anonymous):

yes the interval is [0,2pi]

OpenStudy (anonymous):

and how did you get 2sinxcosx from sin2x? is that a formula?

OpenStudy (raden):

yea, that is a formula ... Ok, for cosx=0, so what wiil u get for x?

OpenStudy (anonymous):

pi/2 and 3pi/2 i got the rest of the answers thank you:)

OpenStudy (raden):

ok right... and for 2sinx - 1 = 0 or sin x = 1/2 solve for x, i sure u can get it to....

OpenStudy (anonymous):

pi/6 and 5pi/6

OpenStudy (raden):

good job...

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