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Mathematics 10 Online
OpenStudy (anonymous):

find dy/dx

OpenStudy (zzr0ck3r):

here dy/dx, here boy...good boy found.

OpenStudy (anonymous):

\[y = \ln (e ^{x} -1)\]

OpenStudy (zzr0ck3r):

so we have the chain rule. what is the outside function?

OpenStudy (anonymous):

ln is outside

OpenStudy (anonymous):

it must be 1/(e^x-1) * e^x

OpenStudy (zzr0ck3r):

right what is dy/dx(ln(x))?

OpenStudy (zzr0ck3r):

yes

OpenStudy (anonymous):

ok...thanks!

OpenStudy (anonymous):

i mean e^x/(e^x-1)

OpenStudy (zzr0ck3r):

:)

OpenStudy (anonymous):

|dw:1346752215288:dw|

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