Question

A man wishes to fence a rectangular lot. if the used material costing $1.50 a meter for the front of the lot and the material costing $1.30 a meter for the other 3 sides, the fence will cost $380. if he uses the cheaper material from all sides of the lot the fence will cost $364. Find the dimension of the lot.

Answer 1

what equations u got ?

Answer 2

x=width of the lot
y=length of its lot (front and back of the lot)

1.30(2x)+1.30(y)+1.50(y)=380
1.30(2x)+1.30(2y)=364

Answer 3

these are correct
need help solving these??
i m getting 60,80.

Answer 4

just subtract 2nd equation from 1st equation.

Answer 5

i need a complete solution :)

Answer 6

If you want the solition you have it in the third post above this post. Do you want the steps?

Answer 7

but u are clear with equations right?
i will give complete solution starting from the equations,ok??

Answer 8

I think that might be helpful @hartnn

Answer 9

ok.. i want a complete solution from the equation that i have given..:)

Answer 10

thank you:)

Answer 11

ok,
1.30(2x)+1.30(y)+1.50(y)=380---->(1)
1.30(2x)+1.30(2y)=364---------->(2)

subtracting (2) from (1),
0.2y=16
y=80=length of lot

substitute back in (2),
2.6x=364-2.6*80=156
x=156/2.6=60=width

Answer 12

i skipped a step
2.8y-2.6y=380-364
0.2y=16

Answer 13

ask if still have doubts somewhere.