Question

the sum of five consecutive even integers is 520.find the smallest integer

Answer 1

Hint: if x is the first even integer, what are the other 4?

Answer 2

Assume the EVEN integers to be 2(n-2), 2(n-1), 2n, 2(n+1), 2(n+2).
Now their sum is 10n which is 520, giving n as 52.
NOW, the smallest number is 2(n-2), which is 2(52-2), i.e, 100

Answer 3

thank you

Answer 4

:)