Given: AB is diameter, BC is tangent to circle O.

Prove: AXB~ABC

Question

Given: AB is diameter, BC is tangent to circle O.

Prove: AXB~ABC

anonymous · Answer

attachment

anonymous · Answer

Hmm, ok, seeing a couple things here ..

anonymous · Answer

There you are. :)

anonymous · Answer

Angle CBA is right angle, but not for reason given. It is not inscribed in the circle.

anonymous · Answer

Sorry for delay, was giving help on 3D coordinates in space...

anonymous · Answer

Looks like you have those two reasons switched in lines 3 and 4.

anonymous · Answer

Likewise, lines 5 and 6 need to be switched.

anonymous · Answer

I can't see those any longer, I cleared the sheet.

anonymous · Answer

SO far i have, AB is diameter, BC is tangent to circle O: GIVEN

anonymous · Answer

anonymous · Answer

Angle A = Angle A: REFLEXIVE

anonymous · Answer

There we go. *FacePalm*

anonymous · Answer

I think you can take it from here.  :-)

anonymous · Answer

Yes, mind if i post another Screeny for you to look over?

anonymous · Answer

Go ahead. If I'm wandering around elsewhere, just tag my name to it @Cliffsedge

anonymous · Answer

attachment

anonymous · Answer

@CliffSedge

anonymous · Answer

Looks good to me.

anonymous · Answer

Thanks very much!