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factor the trinomial... 8x^2+5x-3
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8 = 2*2*2 -3 = 3*-1 -3 = -3 * 1 we need to combine these factors to give a product = -3 and sum = middle value + 5
yes thats what i got but then i got confused here
\[8x(x+1)-(3(x+3)...\]
8 * 1 and 1 * -3 does it
so its (8x - 3)(x + 1 )
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'inside' and 'outside' give + 5x |dw:1346790107508:dw|
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