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Mathematics 19 Online
OpenStudy (anonymous):

if x^2+bx+13 is factorable, what are the only 2 possible values for b?

OpenStudy (anonymous):

ok, what r the factors of 13?

OpenStudy (anonymous):

1 right

OpenStudy (anonymous):

13 into 1 = 13

OpenStudy (anonymous):

right so the only 2 possible values for b would be 13, 1?

OpenStudy (anonymous):

also, -13 into -1 = 13

OpenStudy (anonymous):

no noo

OpenStudy (anonymous):

ok. so the two possible values for b would be what

OpenStudy (anonymous):

x^2+13x+ x +13 x^2 -13x - x +13

OpenStudy (anonymous):

so +13 and -13?

OpenStudy (anonymous):

are the only two possible values for b

OpenStudy (anonymous):

x^2+13x+ x +13 x^2+14x +13 x^2 -13x - x +13 x^2 -14x +13 14 and -14

OpenStudy (anonymous):

14 and -14 is the answer?

OpenStudy (anonymous):

yes

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