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If the position of an object is given by s(t)=−85t+2 feet, then at t=−4 seconds, the velocity of the object is the speed of the object is the acceleration of the object is
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The velocity of that object will be the first derivative, and the acceleration will be the second derivative.
\[s'(t) = -85\\s''(t) = 0 \]
Now plug -4 in.
Does that help?
yes thanks!
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You're welcome :)
the speed cant be zero can it?
No, it can't.
ok i got it thanks!
yw
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