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Mathematics 12 Online
OpenStudy (anonymous):

If the position of an object is given by s(t)=−85t+2 feet, then at t=−4 seconds, the velocity of the object is the speed of the object is the acceleration of the object is

Parth (parthkohli):

The velocity of that object will be the first derivative, and the acceleration will be the second derivative.

Parth (parthkohli):

\[s'(t) = -85\\s''(t) = 0 \]

Parth (parthkohli):

Now plug -4 in.

Parth (parthkohli):

Does that help?

OpenStudy (anonymous):

yes thanks!

Parth (parthkohli):

You're welcome :)

OpenStudy (anonymous):

the speed cant be zero can it?

Parth (parthkohli):

No, it can't.

OpenStudy (anonymous):

ok i got it thanks!

Parth (parthkohli):

yw

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