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In circle A shown below, Segment BD is a diameter and the measure of Arc CB is 36°. http://learn.flvs.net/webdav/assessment_images/educator_geometry_v14/pool_Geom_3641_0801_04/image0054e847c99.gif What is the measure of ∡DBC?
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@cwrw238 @Hero @jim_thompson5910 @ParthKohli
Inscribed angles are half of the arc which they cut. The diameter divides the circle into 2 180º arcs.
okay....
so its18?
No, that's the measure of angle CDB.
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then how do i find DBC?
angle DBC has vertex at B. Arc BCD is half the circle, so =180º subtract from that arc BC or 36º to get arc CD.
Angle DBC is half of arc CD.
162?
sry typo 72
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Correct.
okay thank you
You can also confirm that using the three angles of that triangle, 90+18+72 = 180.
okay! :)
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