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Mathematics 14 Online
OpenStudy (anonymous):

Solve A=h/2(b1 + b2) for h. Is this like the one before? We are a bit confused.

OpenStudy (anonymous):

We know:\[ \begin{align} A&=\frac{h(b_1+b_2)}{2}\implies\\ 2A&=h(b_1+b_2)\implies\\ \frac{2A}{b_1+b_2}&=h \end{align} \]And, we are done.

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