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\[(3x+1)\times 2x-x^2\times 3\] \[=6x^2+2x-3x^2\] \[=3x^2+2x\] that is the best you can do
well, you could write \(x(3x+2)\) if you like for the numerator nothing cancels, that is it
final answer would be \[\frac{x(3x+2)}{(3x+1)^2}\]
thank you so much! im going to do a similar one, would you mind checking it for me?
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