Question

how to solve this 2x^3-8x=0

Answer 1

factor out 2x

\[\implies 2x(x^2 - 4) = 0\]
do you see that the second factor is difference of two squares?
\[\implies 2x(x+2)(x-2) = 0\]
do you know how to solve for x now?

Answer 2

yes thank you!

Answer 3

welcome

Answer 4

cubic equation so we wolud expect 3 answers.factor out 2x. x becomes zero.dats our first root. we have x^2-4 left. that obviously a difference of two squares so you'll get + or -2. so your 3 root have been found now...hope that was fun

Answer 5

thanks niikofi12

Answer 6

my utmost pleasure