-2(v-7)-6v=8(4-v)-3
-2v +14 - 6v = 32 - 8v - 3 distribute.
just complete swin2013's work. \[ \large -2v-6v+8v=32-3-14 \] now perform all the operations and post what u get
that's the problem... the 8v's cancel out.
im sorry but i dont know how to do it thanks anyways guys
did you write the problem wrong? Or are they looking for no real numbers
no jus to solve the equation
it is fine \[ \large 0=15 \] which is not true. this means that equation has no solutions. unless, as swin2013 said, you wrote the equation incorrectly.
no im pretty sure i wrote it rite
so 0=15 means the equation has no solutions.
yep. agree with helder. no real solutions
how do u guys do the problem step by step i have a test tomorrow and i wanna be raedy
remember to combine like terms and distribute carefully. Combine the terms with variables first. try to put them in one side of the equation. then combine the numbers and put them in the other side of the equation. the goal is to solve for the variable (or the letter)
thank u
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