Question

factor 6x^2+19x+10

Answer 1

please use the quadratic formula \[-b \pm \sqrt{b ^{2}-4ac} \over 2a\]

where a=6 b=19 c=10 you should get the answer x1= -2/3 x2= -5/2 therefore the roots will of the equation will be (x+(2/3)) and (x=(5/2))

Answer 2

*= should be plus sign.

Answer 3

I hope this will help you answer the problem.