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OpenStudy (anonymous):
i need help simplifying!
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OpenStudy (anonymous):
hartnn (hartnn):
can u factor \(n^2-n-12\) ?
hartnn (hartnn):
what are the factors of -12 such that their sum is -1 ??
OpenStudy (anonymous):
sorry i kind of went ahead, but my final answer was |dw:1346826705460:dw|
OpenStudy (anonymous):
i think...
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OpenStudy (anonymous):
????
hartnn (hartnn):
are u sure about n-3 ? shouldn't it be n+3 ?
hartnn (hartnn):
the negative sign and n+2 is correct.
hartnn (hartnn):
what factors u got of \(n^2-n-12 \) ?
OpenStudy (anonymous):
your right it was n+3
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OpenStudy (anonymous):
thanks
hartnn (hartnn):
welcome :)
OpenStudy (anonymous):
do it by crross multiplication
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