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Mathematics 17 Online
OpenStudy (anonymous):

What is the mean absolute deviation of 111, 135, 115, 120, 145, 130?

OpenStudy (unklerhaukus):

so the mean is 126 what are the absolute deviations of each

OpenStudy (amistre64):

we can use an equivalent spread of smaller numbers by subtracting the same amount from each data point {111, 135, 115, 120, 145, 130} - 110 sum {1, 25, 5, 10, 35, 20} = 96; 96/6 = 16 that might be simpler to work with

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